Java split string with "||" taking it as regex instead of string

Question

I have the following string "ABC" and "AAA||BBB"

I am trying to split it using the characters "||" but the split method is taking this as a regex expression, returning an array of characters instead of {"ABC"} and {"AAA", "BBB"}

I have tried scaping the bar with a back slash, but that didn't work.

How can I make the split method to take "||" as a String and not as a regex?

Thanks

possible duplicate of [String.split() \*not\* on regular expression?](http://stackoverflow.com/questions/6374050/string-split-not-on-regular-expression) — Eric, Apr 30 '13 at 18:17

score 5 · Accepted Answer · answered Apr 30 '13 at 18:14

5

Escape the pipes

Use \\|\\| instead

answered Apr 30 '13 at 18:14

FDinoff

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double back slash... that solved it! I was trying with only one. Thanks! – marimaf Apr 30 '13 at 18:21
You need to escape the slash. This leads to a double slash. – FDinoff Apr 30 '13 at 18:22
just did. StackoverFlow has a time restriction to accept answers, I had to wait. – marimaf Apr 30 '13 at 20:39

score 4 · Answer 2 · answered Apr 30 '13 at 18:20

4

If you don't want to deal with escaping then you can use Pattern#quote:

String[] tok = "AAA||BBB".split(Pattern.quote("||"));

OR simple:

String[] tok = "AAA||BBB".split("\\Q||\\E"));

answered Apr 30 '13 at 18:20

anubhava

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score 0 · Answer 3 · answered Apr 30 '13 at 19:10

0

   String[] result = "The||man is very happy.".split("\\|\\|");

    for (int x=0; x<result.length; x++){

        System.out.print(result[x]);
     }

There you go its simple

answered Apr 30 '13 at 19:10

Junaid Hassan

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Java split string with "||" taking it as regex instead of string

3 Answers3