127

I have one big layout, and one smaller layout inside of it.

How do I create a line border around the small layout?

Michael Petrotta
  • 56,954
  • 26
  • 136
  • 173
user1302569
  • 6,651
  • 12
  • 44
  • 64
  • Have You tried http://stackoverflow.com/questions/3496269/how-to-put-a-border-around-an-android-textview ? – sandrstar Feb 27 '13 at 11:53

9 Answers9

272

Sure. You can add a border to any layout you want. Basically, you need to create a custom drawable and add it as a background to your layout. example:

Create a file called customborder.xml in your drawable folder:

<?xml version="1.0" encoding="UTF-8"?>
 <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
   <corners android:radius="20dp"/> 
   <padding android:left="10dp" android:right="10dp" android:top="10dp" android:bottom="10dp"/>
   <stroke android:width="1dp" android:color="#CCCCCC"/>
 </shape>

Now apply it as a background to your smaller layout:

<LinearLayout android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="@drawable/customborder">

That should do the trick.

Also see:

Anup Cowkur
  • 19,813
  • 6
  • 48
  • 82
26

Creat XML called border.xml in drawable folder as below :

<?xml version="1.0" encoding="utf-8"?>
 <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
  <item> 
    <shape android:shape="rectangle">
      <solid android:color="#FF0000" /> 
    </shape>
  </item>   
    <item android:left="5dp" android:right="5dp"  android:top="5dp" >  
     <shape android:shape="rectangle"> 
      <solid android:color="#000000" />
    </shape>
   </item>    
 </layer-list>

then add this to linear layout as backgound as this:

     android:background="@drawable/border"
KDeogharkar
  • 11,502
  • 7
  • 51
  • 93
11

Try this:

For example, let's define res/drawable/my_custom_background.xml as:

(create this layout in your drawable folder) layout_border.xml

  <?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item>
        <shape android:shape="rectangle">
            <stroke android:width="2dp" android:height="2dp"
                android:color="#FF0000" />
            <solid android:color="#000000" />
            <padding android:left="1dp" android:top="1dp" android:right="1dp"
                android:bottom="1dp" />

            <corners android:radius="1dp" android:bottomRightRadius="5dp"
                android:bottomLeftRadius="0dp" android:topLeftRadius="5dp"
                android:topRightRadius="0dp" />
        </shape>
    </item>

</layer-list>

main.xml

<LinearLayout 
    android:layout_gravity="center"
    android:layout_width="200dp" 
    android:layout_height="200dp"   
    android:background="@drawable/layout_border" />
</LinearLayout>
Android_coder
  • 9,303
  • 2
  • 15
  • 23
11

Create a one xml file in drawable folder

<stroke
    android:width="2dp"
    android:color="#B40404" />

<padding
    android:bottom="5dp"
    android:left="5dp"
    android:right="5dp"
    android:top="5dp" />

<corners android:radius="4dp" />

Now call this xml to your small layout background

android:background="@drawable/yourxml"

Vani
  • 131
  • 1
  • 4
5

This solution will only add the border, the body of the LinearLayout will be transparent.

First, Create this border drawable in the drawable folder, border.xml

<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android= "http://schemas.android.com/apk/res/android"
    android:shape="rectangle">
    <stroke android:width="2dp" android:color="#ec0606"/>
    <corners android:radius="10dp"/>
</shape>

Then, in your LinearLayout View, add the border.xml as the background like this

<LinearLayout 
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical"
    android:background="@drawable/border">
s-hunter
  • 17,762
  • 11
  • 67
  • 105
4

you can do it Pragmatically also 

  GradientDrawable gradientDrawable=new GradientDrawable();
   gradientDrawable.setStroke(4,getResources().getColor(R.color.line_Input));

Then set the background of layout as :

LinearLayout layout = (LinearLayout ) findViewById(R.id.ayout); layout .setBackground(gradientDrawable);
Vikram singh
  • 246
  • 3
  • 14
3

I'll add Android docs link to other answers.

https://developer.android.com/guide/topics/resources/drawable-resource.html#Shape

It describes all attributes of the Shape Drawable and stroke among them to set the border.

Example:

<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
  <stroke android:width="1dp" android:color="#F00"/>
  <solid android:color="#0000"/>
</shape>

Red border with transparent background.

mortalis
  • 1,764
  • 19
  • 31
1

Don't want to create a drawable resource?

  <FrameLayout
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:background="@android:color/black"
    android:minHeight="128dp">

    <FrameLayout
      android:layout_width="match_parent"
      android:layout_height="match_parent"
      android:layout_margin="1dp"
      android:background="@android:color/white">

      <TextView ... />
    </FrameLayout>
  </FrameLayout>
Jeffrey Blattman
  • 21,054
  • 8
  • 74
  • 127
0

Try This in your res/drawable

    <?xml version="1.0" encoding="UTF-8"?><layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
  <shape
    android:shape="rectangle">
    <padding android:left="15dp"
        android:right="15dp"
        android:top="15dp"
        android:bottom="15dp"/>
    <stroke android:width="10dp"
        android:color="@color/colorPrimary"/>
  </shape>
</item><item android:left="-5dp"
        android:right="-5dp"
        android:top="-5dp"
        android:bottom="-5dp">
  <shape android:shape="rectangle">
    <solid android:color="@color/background" />
  </shape></item></layer-list>
Akash Tongare
  • 1
  • 3