4

I just discovered something.

echo $var1 , " and " , $var2;

is the same as:

echo $var1 . " and " . $var2;

What is the actual string concatenation operator in php? Should I be using . or ,?

Meredith
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bbtang
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    now we do a big random to pick whose answer is right! – RageZ Sep 29 '09 at 08:20
  • omg.. u r right? This question is too stupid (duh, I am the stupid question-er).. i will choose the one that has highest vote. Thanks guys(its really hard for me to choose the best answer, I just refresh this page, and I got lots of answers z_z)!! – bbtang Sep 29 '09 at 08:24

8 Answers8

14

The . operator is the concatenation operator. Your first example only works because the echo 'function' (technically it's a language construct, but lets not split hairs) accepts more than one parameter, and will print each one.

So your first example is calling echo with more than one parameter, and they are all being printed, vs. the second example where all the strings are being concatentated and that one big string is being printed.

Matthew Scharley
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4

The actual concatenation is . (period). Using , (comma) there, you are passing multiple arguments to the echo function. (Actually, echo is not a function but a PHP language construct, which means you can omit the parentheses around the argument list that are required for actual function calls.)

Greg Hewgill
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3

In the first case you just echo 3 different strings.

In the second case you concatenate the 3 strings and then echo the output.

So the answer is that, in order to concatenate strings you should use the dot (.)

Anax
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2

".". The other just writes several values independently, without actually concatenating the string.
See also PHP echo reference, the "," variant will only work with methods accepting multiple parameters.

Lucero
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2

"." concatenates, "," can only be used for echo which is a language construct (sort of a function)

also see: Difference between period and comma?

Community
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knittl
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1

Using a comma doesn't actually concatenate the strings.

See this answer to another question.

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kkyy
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1

The "." is the correct concatenate operator. "echo" also accepts ",", treating it as if you are passing in a series of arguments to the "echo" method and then echoing each one. It's not truly concatenating the strings.

Mike A.
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0

nop it's because echo could take more then one argument, it would do the print each arguments

RageZ
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