Writing a Python list of lists to a csv file

Question

I have a long list of lists of the following form ---

a = [[1.2,'abc',3],[1.2,'werew',4],........,[1.4,'qew',2]]

i.e. the values in the list are of different types -- float,int, strings.How do I write it into a csv file so that my output csv file looks like

1.2,abc,3
1.2,werew,4
.
.
.
1.4,qew,2

score 347 · Accepted Answer · edited Jun 26 '19 at 12:45

347

Python's built-in CSV module can handle this easily:

import csv

with open("output.csv", "wb") as f:
    writer = csv.writer(f)
    writer.writerows(a)

This assumes your list is defined as a, as it is in your question. You can tweak the exact format of the output CSV via the various optional parameters to csv.writer() as documented in the library reference page linked above.

Update for Python 3

import csv

with open("out.csv", "w", newline="") as f:
    writer = csv.writer(f)
    writer.writerows(a)

edited Jun 26 '19 at 12:45

bucky

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answered Dec 26 '12 at 07:46

Amber

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96

For Python 3 compatibility, remove the "b" from "wb". – Vlad V May 14 '15 at 11:54
28

With Python 3 - open('output.csv', 'w', newline=''). I get an extra line if I omit the newline parameter. https://docs.python.org/3/library/csv.html#csv.writer – Spas Jul 02 '15 at 15:50
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In python3 I had to use open('output.csv', 'w', newline="") – Tim Mottram Apr 06 '17 at 09:25
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WOW that python 3 error is very unhelpful. Thanks @vladV (a bytes-like object is required, not 'str'). It kinda makes sense in hindsight, but not informative of where to look at all. – Rambatino May 25 '18 at 07:30
@VladV I think your comment should be mentioned on Amber's answer. – SDG Jun 18 '19 at 10:11
If you get error "TypeError: 'newline' is an invalid keyword argument for this function" just remove the newline argument. with open(file_name, "w") as f: – tlalco Feb 06 '20 at 13:20
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@tlalco that probably means you're using Python 2, in which case you should use the first code block rather than the second. (It also means you should consider switching to Python 3.) – Amber Feb 07 '20 at 02:53

score 37 · Answer 2 · answered Jan 22 '15 at 19:42

37

You could use pandas:

In [1]: import pandas as pd

In [2]: a = [[1.2,'abc',3],[1.2,'werew',4],[1.4,'qew',2]]

In [3]: my_df = pd.DataFrame(a)

In [4]: my_df.to_csv('my_csv.csv', index=False, header=False)

answered Jan 22 '15 at 19:42

Akavall

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I don't think should use `pandas` if built-in library `csv` can do it. – Simin Jie Sep 28 '17 at 02:19
7

i like pandas because its powerful – dorbodwolf Dec 10 '17 at 13:24
19

pandas is powerful, sure, but I'm not going to use a McLaren to drive to the corner store next door. – hallo Aug 15 '19 at 04:12

score 32 · Answer 3 · edited Feb 16 '15 at 11:43

32

import csv
with open(file_path, 'a') as outcsv:   
    #configure writer to write standard csv file
    writer = csv.writer(outcsv, delimiter=',', quotechar='|', quoting=csv.QUOTE_MINIMAL, lineterminator='\n')
    writer.writerow(['number', 'text', 'number'])
    for item in list:
        #Write item to outcsv
        writer.writerow([item[0], item[1], item[2]])

official docs: http://docs.python.org/2/library/csv.html

edited Feb 16 '15 at 11:43

Mike H-R

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answered Dec 26 '12 at 07:48

Dmitry Zagorulkin

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This would get my +1 if you could explain your answer with some comments. – Burhan Khalid Dec 26 '12 at 07:50
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`writerow` does not take multiple arguments. – Amber Dec 26 '12 at 07:51
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>>> w.writerow("a", "b", "c") Traceback (most recent call last): File "", line 1, in TypeError: writerow() takes exactly one argument (3 given) – Amber Dec 26 '12 at 09:26
@Amber what version of python do you use? – Dmitry Zagorulkin Dec 26 '12 at 09:30
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@Amber excuse me. i missed [] – Dmitry Zagorulkin Dec 26 '12 at 09:32

score 14 · Answer 4 · edited Jul 28 '15 at 03:17

Using csv.writer in my very large list took quite a time. I decided to use pandas, it was faster and more easy to control and understand:

 import pandas

 yourlist = [[...],...,[...]]
 pd = pandas.DataFrame(yourlist)
 pd.to_csv("mylist.csv")

The good part you can change somethings to make a better csv file:

 yourlist = [[...],...,[...]]
 columns = ["abcd","bcde","cdef"] #a csv with 3 columns
 index = [i[0] for i in yourlist] #first element of every list in yourlist
 not_index_list = [i[1:] for i in yourlist]
 pd = pandas.DataFrame(not_index_list, columns = columns, index = index)

 #Now you have a csv with columns and index:
 pd.to_csv("mylist.csv")

score 11 · Answer 5 · answered Mar 04 '15 at 19:44

If for whatever reason you wanted to do it manually (without using a module like csv,pandas,numpy etc.):

with open('myfile.csv','w') as f:
    for sublist in mylist:
        for item in sublist:
            f.write(item + ',')
        f.write('\n')

Of course, rolling your own version can be error-prone and inefficient ... that's usually why there's a module for that. But sometimes writing your own can help you understand how they work, and sometimes it's just easier.

score 6 · Answer 6 · answered Dec 20 '13 at 09:40

6

Ambers's solution also works well for numpy arrays:

from pylab import *
import csv

array_=arange(0,10,1)
list_=[array_,array_*2,array_*3]
with open("output.csv", "wb") as f:
    writer = csv.writer(f)
    writer.writerows(list_)

answered Dec 20 '13 at 09:40

Semjon Mössinger

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score 6 · Answer 7 · answered Jul 16 '19 at 08:29

6

If you don't want to import csv module for that, you can write a list of lists to a csv file using only Python built-ins

with open("output.csv", "w") as f:
    for row in a:
        f.write("%s\n" % ','.join(str(col) for col in row))

answered Jul 16 '19 at 08:29

fabda01

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score 4 · Answer 8 · answered Feb 14 '19 at 00:54

How about dumping the list of list into pickle and restoring it with pickle module? It's quite convenient.

>>> import pickle
>>> 
>>> mylist = [1, 'foo', 'bar', {1, 2, 3}, [ [1,4,2,6], [3,6,0,10]]]
>>> with open('mylist', 'wb') as f:
...     pickle.dump(mylist, f) 


>>> with open('mylist', 'rb') as f:
...      mylist = pickle.load(f)
>>> mylist
[1, 'foo', 'bar', {1, 2, 3}, [[1, 4, 2, 6], [3, 6, 0, 10]]]
>>>

score 3 · Answer 9 · edited Apr 02 '15 at 21:33

Make sure to indicate lineterinator='\n' when create the writer; otherwise, an extra empty line might be written into file after each data line when data sources are from other csv file...

Here is my solution:

with open('csvfile', 'a') as csvfile:
    spamwriter = csv.writer(csvfile, delimiter='    ',quotechar='|', quoting=csv.QUOTE_MINIMAL, lineterminator='\n')
for i in range(0, len(data)):
    spamwriter.writerow(data[i])

score 0 · Answer 10 · answered Dec 16 '19 at 19:55

I got an error message when following the examples with a newline parameter in the csv.writer function. The following code worked for me.

 with open(strFileName, "w") as f:
    writer = csv.writer(f, delimiter=',',  quoting=csv.QUOTE_MINIMAL)
    writer.writerows(result)

IAmBotmaker · Answer 11 · 2021-02-21T18:31:21.923

0

In case of exporting lll list of lists of lists to .csv, this will work in Python3:

import csv
with open("output.csv", "w") as f:
    writer = csv.writer(f)
    for element in lll:
        writer.writerows(element)

edited Feb 21 '21 at 18:31

answered Feb 20 '21 at 16:24

IAmBotmaker

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Writing a Python list of lists to a csv file

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