How can I use awk to display some certain fields in a text file?

Question

I have a text file like this:

1 http 2 3 4 5 
2 dns 3 4 
3 ftp 3 4 5 6 8 

I want the output to be like this:

http 2 3 4 5 
dns 3 4 
ftp 3 4 5 6 8 

Node that I just want to omit the first column in that file and the fields number in a certain line is not fixed.

Can I accomplish this goal using awk?

Answer 1

You can also use cut: cut -d' ' -f2-.

Edit: If you have to use awk, try awk '{$1=""; print $0}'

Answer 2

something like this maybe?

awk '{$1 =""; print }' file

Answer 3

If you don't care about the the field separators remaining in place, you can do this:

awk '{$1=""}1' filename

(Assuming filename is where you stored your data)

Answer 4

Drats, I was going to give you an Awk solution, then recommend cut. It looks like others have beaten me to the punch.

However, I see no sed solution yet!

$ sed -n `s/^[^ ][^ ]*//p` yourfile.txt

Answer 5

sed 's/^..//g' your_file

above should work based on the condition that the first field is always of a single character.

or in perl:

perl -pe 's/^[^\s]*\s//g' your_file