Use preg_match to return true if $var includes only (A-Z, a-z, 0-9 and -)

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regular expression for letters, numbers and - _

I would like to return true if the $var only includes (A-Z, a-z, 0-9 and -)

Something like: (this preg_match is to check if $var is mail, but I need the above)

if (!preg_match("/^[-!#$%&\'*+\\.\/0-9=?A-Z^_`{|}~]+@([-0-9A-Z]+\.)+([0-9A-Z]){2,4}$/i", $var))
    return false;
return true;

Any ideas? Im new with preg_match.

Is this an email address? if so dont use a regular expression to check email addresses use the php filters. looks like email but only includes (A-Z, a-z, 0-9 and -) is weird — , Oct 25 '12 at 21:23

enrico.bacis · Accepted Answer · 2012-10-25T21:34:38.947

2

You need to use this preg_match with the code you provided:

preg_match("/^[A-Z0-9-]+$/i", $var)

It will match if $var includes only (A-Z, a-z, 0-9 and -) and is at least 1 character long. If you want to match also empty strings turn the + in a *.

edited Oct 25 '12 at 21:34

answered Oct 25 '12 at 21:24

enrico.bacis

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will it return true or false ? – Phoenix Mar 28 '16 at 15:13
@Phoenix: preg_match() returns 1 if the pattern matches given subject, 0 if it does not, or FALSE if an error occurred. ( http://php.net/manual/en/function.preg-match.php ) – enrico.bacis Mar 28 '16 at 16:13

Use preg_match to return true if $var includes only (A-Z, a-z, 0-9 and -)

1 Answers1