Open file dialog and select a file using WPF controls and C#

Question

I have a TextBox named textbox1 and a Button named button1. When I click on button1 I want to browse my files to search only for image files (type jpg, png, bmp...). And when I select an image file and click Ok in the file dialog I want the file directory to be written in the textbox1.text like this:

textbox1.Text = "C:\myfolder\myimage.jpg"

score 452 · Accepted Answer · edited Apr 02 '14 at 17:59

452

Something like that should be what you need

private void button1_Click(object sender, RoutedEventArgs e)
{
    // Create OpenFileDialog 
    Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();



    // Set filter for file extension and default file extension 
    dlg.DefaultExt = ".png";
    dlg.Filter = "JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif"; 


    // Display OpenFileDialog by calling ShowDialog method 
    Nullable<bool> result = dlg.ShowDialog();


    // Get the selected file name and display in a TextBox 
    if (result == true)
    {
        // Open document 
        string filename = dlg.FileName;
        textBox1.Text = filename;
    }
}

edited Apr 02 '14 at 17:59

Community

1
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answered Apr 25 '12 at 12:08

Klaus78

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23

if (result.HasValue && result.Value) instead of if (result == true) – eflles Apr 26 '14 at 10:33
2

@efles what is the value your way provides over the official sample code at http://msdn.microsoft.com/en-us/library/microsoft.win32.openfiledialog.aspx ? – Dirk Bester Apr 30 '14 at 18:09
7

@eflles The sample is technically correct. From http://msdn.microsoft.com/en-us/library/2cf62fcy.aspx: *When you perform comparisons with nullable types, if the value of one of the nullable types is null and the other is not, all comparisons evaluate to false except for != (not equal).* However I suppose it could be argued whether this is an exploitation of this technicality (I personally think it's OK in this case). – Ohad Schneider Jul 01 '14 at 22:00

score 24 · Answer 2 · answered May 31 '13 at 16:50

var ofd = new Microsoft.Win32.OpenFileDialog() {Filter = "JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif"}; 
var result = ofd.ShowDialog();
if (result == false) return;
textBox1.Text = ofd.FileName;

Open file dialog and select a file using WPF controls and C#

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