The task: Determine the average molar mass of the atmosphere - each for the moist air and the dry air. One example that I have calculated is this one: I have the gas Nitrogen and the percentage for the moist air(**77,0%**) and the percentage for the dry air(**78,08%**) aswell as the molar mass(**28,014**) in $$\left(\frac{g}{mol}\right)$$

**My solution**: $$\text{Nitrogen}= 0,78 \cdot 0,28+ 0,77 \cdot 0,28 = 43,4 \frac{g}{mol}$$

Is that correct? Kind regards, iloveoov.