How to convert a Java 8 Stream to an Array?

Question

What is the easiest/shortest way to convert a Java 8 Stream into an array?

Answer 1

The easiest method is to use the toArray(IntFunction<A[]> generator) method with an array constructor reference. This is suggested in the API documentation for the method.

String[] stringArray = stringStream.toArray(String[]::new);

What it does is find a method that takes in an integer (the size) as argument, and returns a String[], which is exactly what (one of the overloads of) new String[] does.

You could also write your own IntFunction:

Stream<String> stringStream = ...;
String[] stringArray = stringStream.toArray(size -> new String[size]);

The purpose of the IntFunction<A[]> generator is to convert an integer, the size of the array, to a new array.

Example code:

Stream<String> stringStream = Stream.of("a", "b", "c");
String[] stringArray = stringStream.toArray(size -> new String[size]);
Arrays.stream(stringArray).forEach(System.out::println);

Prints:

a
b
c

Answer 2

If you want to get an array of ints, with values from 1 to 10, from a Stream<Integer>, there is IntStream at your disposal.

Here we create a Stream with a Stream.of method and convert a Stream<Integer> to an IntStream using a mapToInt. Then we can call IntStream's toArray method.

Stream<Integer> stream = Stream.of(1,2,3,4,5,6,7,8,9,10);
//or use this to create our stream 
//Stream<Integer> stream = IntStream.rangeClosed(1, 10).boxed();
int[] array =  stream.mapToInt(x -> x).toArray();

Here is the same thing, without the Stream<Integer>, using only the IntStream:

int[]array2 =  IntStream.rangeClosed(1, 10).toArray();

Answer 3

You can convert a java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more, first, let's Create a list of string filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array :

Stream<String> stringStream = Arrays.stream(stringList);

we can now perform some operations on this stream Ex:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

and finally convert it to a java 8 Array using these methods:

1-Classic method (Functional interface)

IntFunction<String[]> intFunction = new IntFunction<String[]>() {
    @Override
    public String[] apply(int value) {
        return new String[value];
    }
};


String[] myNewArray = myNewStream.toArray(intFunction);

2 -Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

3- Method reference

String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

Answer 4

Convert text to string array where separating each value by comma, and trim every field, for example:

String[] stringArray = Arrays.stream(line.split(",")).map(String::trim).toArray(String[]::new);

Answer 5

You can create a custom collector that convert a stream to array.

public static <T> Collector<T, ?, T[]> toArray( IntFunction<T[]> converter )
{
    return Collectors.collectingAndThen( 
                  Collectors.toList(), 
                  list ->list.toArray( converter.apply( list.size() ) ) );
}

and a quick use

List<String> input = Arrays.asList( ..... );

String[] result = input.stream().
         .collect( CustomCollectors.**toArray**( String[]::new ) );

Answer 6

Using the toArray(IntFunction<A[]> generator) method is indeed a very elegant and safe way to convert (or more correctly, collect) a Stream into an array of the same type of the Stream.

However, if the returned array's type is not important, simply using the toArray() method is both easier and shorter. For example:

    Stream<Object> args = Stream.of(BigDecimal.ONE, "Two", 3);
    System.out.printf("%s, %s, %s!", args.toArray());

Answer 7

Stream<Integer> stream = Stream.of(1, 2, 3, 4, 5, 6);

int[] arr=   stream.mapToInt(x->x.intValue()).toArray();

Answer 8

import java.util.List;
import java.util.stream.Stream;

class Main {

    public static void main(String[] args) {
        // Create a stream of strings from list of strings
        Stream<String> myStreamOfStrings = List.of("lala", "foo", "bar").stream();

        // Convert stream to array by using toArray method
        String[] myArrayOfStrings = myStreamOfStrings.toArray(String[]::new);

        // Print results
        for (String string : myArrayOfStrings) {
            System.out.println(string);
        }
    }
}

Try it out online: https://repl.it/@SmaMa/Stream-to-array

Answer 9

     Stream<Integer> stream = Stream.of(1, 2, 3, 4, 5, 6);

     Integer[] integers = stream.toArray(it->new Integer[it]);

Answer 10

you can use the collector like this

  Stream<String> io = Stream.of("foo" , "lan" , "mql");
  io.collect(Collectors.toCollection(ArrayList<String>::new));

Answer 11

You can do it in a few ways.All the ways are technically the same but using Lambda would simplify some of the code. Lets say we initialize a List first with String, call it persons.

List<String> persons = new ArrayList<String>(){{add("a"); add("b"); add("c");}};
Stream<String> stream = persons.stream();

Now you can use either of the following ways.

1. Using the Lambda Expresiion to create a new StringArray with defined size.

   String[] stringArray = stream.toArray(size->new String[size]);

2. Using the method reference directly.

   String[] stringArray = stream.toArray(String[]::new);