can anybody please tell me what's happening here ?
$$1^2=1$$
$$2^2=2+2$$
$$3^2=3+3+3$$
$$x^2 = x+x+\cdots+x \mbox{ ($x$ times)}$$
differentiating both the sides $$2x = 1 + 1 + \cdots+1 \mbox{ ($x$ times)}$$
thank u
can anybody please tell me what's happening here ?
$$1^2=1$$
$$2^2=2+2$$
$$3^2=3+3+3$$
$$x^2 = x+x+\cdots+x \mbox{ ($x$ times)}$$
differentiating both the sides $$2x = 1 + 1 + \cdots+1 \mbox{ ($x$ times)}$$
thank u
When you are getting $$x^2 = x+x+\cdots+x \mbox{ ($x$ times)}$$ then $x$ is a constant no not a variable. So, differentiating both side you will get $0=0$ which is true.