What are some interesting mental math techniques that you know?

Here's one that I got from my Grandmother who got it from a book: To square a two-digit number (from $26$ to $49$), take the number minus $25$ and put that in the first two digits, and then add the square of $50$ minus the number: $$(\text{number}-25)\times100+(50-\text{number})^2$$ For example, to do $47^2$ we have $47-25=22$ for the first two digits and $(50-47)^2=9$ for the last two so we get $47^2=2209$.

Bonus points if you include justification! For this trick, $$100(n-25)+(50-n)^2=100n-2500+2500-100n+n^2=n^2$$

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    Why the downvotes? –  Apr 18 '14 at 00:53
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    this question is opinion based, which is against the guidelines of the math stack exchange. – Sidd Singal Apr 18 '14 at 01:19
  • @mathguy There's nothing opinionated about a mental math trick. It either works or it doesn't. How could this possibly result in arguments? –  Apr 18 '14 at 02:18
  • You are asking for the *best* mental tricks -- that sounds opinion based to me... – Thomas Apr 18 '14 at 02:18
  • @Thomas I meant the best mental tricks known to the person answering. I'll edit the question phrasing. –  Apr 18 '14 at 02:20
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    There it's not opinion based anymore. Please don't close. –  Apr 18 '14 at 02:22
  • For those of you who downvoted, do you still consider the question opinion based? Is there anything I could do to make it better? –  Apr 18 '14 at 02:34
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    If you look at the "Related" questions listed on this page, you'll see that there have been many questions on mental math on this site already. It might be worth having a look at a few of them, to see that we are not creating duplications --- indeed, it is possible that the current question should be closed as a duplicate. – Gerry Myerson Apr 20 '14 at 14:01

3 Answers3


Of course, we have the classic trick $$9\times n=(10\times n)-n$$ which works because of distributivity. This can be generalized as follows: $$99n=100n-n$$ so for example $$99\cdot 54=5400-54=5346$$ It also helps simplify generic calculations. E.g., $$17\cdot 8=17\cdot 10-17\cdot 2=170-34=136$$


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Makes multiplication of multi-digit numbers easier. The above is the following problem:

x 365421

This is how they teach multiplication in Japan. You may be thinking, you draw this in your mind? No, there's a shortcut for this method.

Take for instance:

x 32

You can draw it to get the answer. But the drawing is basically giving you a simpler way of solving it. This is how you solve it:


Here's a little tougher one that I did mentally:


Makes mental multiplication of multi-digit numbers easier.

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  • You can visualize a $5\times 6$ array of numbers in your head?! – user7530 Apr 18 '14 at 00:38
  • @user7530 Obviously not this big but for 3/4-digit numbers it's useful. – Shahar Apr 18 '14 at 00:39
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    So... the standard multiplication algorithm, but less efficient. Looks pretty, though, and probably useful as an educational tool more than anything. – Ben Grossmann Apr 18 '14 at 00:41
  • @Omnomnomnom If I did 721 x 341 the standard way it's much more painful than this: http://sketchtoy.com/60373153 – Shahar Apr 18 '14 at 00:56
  • I mean, what you're doing is adding every term in the expansion of the product $(7\cdot 10^2 + 2\cdot 10 + 1)(3 \cdot 10^2 + 4 \cdot 10 + 1)$. The quickness in your usage comes from the fact that you're able to group together the terms of a common power of $10$, and that this happens to work well for you. I'm not sure most would agree that the computation you do is easier than the usual order of adding the terms. – Ben Grossmann Apr 18 '14 at 01:01

Here is a trick to multiply two numbers between 10 and 19 together, say $10 + x$ and $10 + y$: Compute $10 + x + y$, put a zero at the end (multiply by 10), and add $x\cdot y$. Thus $(10+x)(10+y) = 10\cdot(10 + x + y) + xy$.

Easy with algebra. I learned this from my mother who had only an 8th grade education and no algebra.

Hans Engler
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