The sequence is $f = 0, 1, 0, 1, \ldots$

I want to find a general formula for the $n$th element. The sequence starts at $n = 0$ (the $0$ here is not the first element $0$ but rather denotes the $0$th position).

One easy and obvious solution is: $n$th $f = n \bmod 2$. This works because even positions have $0$ and odd positions have $1$.

However, this question is part of a homework and modulus has not been discussed (or part of the syllabus or even a prerequisite). And so I am hesitant to use it.

Is there another way to solve this problem using only basic arithmetic operations (one that a beginning high schooler knows of)?